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Approximations of pi 8/10 https://en.wikipedia.org/wiki/Approximations_of_pi reference science, encyclopedia 2026-05-05T16:19:48.727542+00:00 kb-cron

=== Continued fractions === Besides its simple continued fraction representation [3; 7, 15, 1, 292, 1, 1, ...], which displays no discernible pattern, π has many generalized continued fraction representations generated by a simple rule, including these two.

    π
    =
    
      3
      +
      
        
          
            
              
            
            
              
                
                  1
                  
                    2
                  
                
              
            
          
          
            
              
            
            
              
                6
                +
                
                  
                    
                      
                        
                      
                      
                        
                          
                            3
                            
                              2
                            
                          
                        
                      
                    
                    
                      
                        
                      
                      
                        
                          6
                          +
                          
                            
                              
                                
                                  
                                
                                
                                  
                                    
                                      5
                                      
                                        2
                                      
                                    
                                  
                                
                              
                              
                                
                                  
                                
                                
                                  
                                    6
                                    +
                                    ⋱
                                    
                                  
                                
                              
                            
                          
                        
                      
                    
                  
                
              
            
          
        
      
    
  

{\displaystyle \pi ={3+{\cfrac {1^{2}}{6+{\cfrac {3^{2}}{6+{\cfrac {5^{2}}{6+\ddots \,}}}}}}}}




  
    π
    =
    
      
        
          
            
          
          
            
              4
            
          
        
        
          
            
          
          
            
              1
              +
              
                
                  
                    
                      
                    
                    
                      
                        
                          1
                          
                            2
                          
                        
                      
                    
                  
                  
                    
                      
                    
                    
                      
                        3
                        +
                        
                          
                            
                              
                                
                              
                              
                                
                                  
                                    2
                                    
                                      2
                                    
                                  
                                
                              
                            
                            
                              
                                
                              
                              
                                
                                  5
                                  +
                                  
                                    
                                      
                                        
                                          
                                        
                                        
                                          
                                            
                                              3
                                              
                                                2
                                              
                                            
                                          
                                        
                                      
                                      
                                        
                                          
                                        
                                        
                                          
                                            7
                                            +
                                            
                                              
                                                
                                                  
                                                    
                                                  
                                                  
                                                    
                                                      
                                                        4
                                                        
                                                          2
                                                        
                                                      
                                                    
                                                  
                                                
                                                
                                                  
                                                    
                                                  
                                                  
                                                    
                                                      9
                                                      +
                                                      ⋱
                                                    
                                                  
                                                
                                              
                                            
                                          
                                        
                                      
                                    
                                  
                                
                              
                            
                          
                        
                      
                    
                  
                
              
            
          
        
      
    
    =
    3
    +
    
      
        
          
            
          
          
            
              
                1
                
                  2
                
              
            
          
        
        
          
            
          
          
            
              5
              +
              
                
                  
                    
                      
                    
                    
                      
                        
                          4
                          
                            2
                          
                        
                      
                    
                  
                  
                    
                      
                    
                    
                      
                        7
                        +
                        
                          
                            
                              
                                
                              
                              
                                
                                  
                                    3
                                    
                                      2
                                    
                                  
                                
                              
                            
                            
                              
                                
                              
                              
                                
                                  9
                                  +
                                  
                                    
                                      
                                        
                                          
                                        
                                        
                                          
                                            
                                              6
                                              
                                                2
                                              
                                            
                                          
                                        
                                      
                                      
                                        
                                          
                                        
                                        
                                          
                                            11
                                            +
                                            
                                              
                                                
                                                  
                                                    
                                                  
                                                  
                                                    
                                                      
                                                        5
                                                        
                                                          2
                                                        
                                                      
                                                    
                                                  
                                                
                                                
                                                  
                                                    
                                                  
                                                  
                                                    
                                                      13
                                                      +
                                                      ⋱
                                                    
                                                  
                                                
                                              
                                            
                                          
                                        
                                      
                                    
                                  
                                
                              
                            
                          
                        
                      
                    
                  
                
              
            
          
        
      
    
  

{\displaystyle \pi ={\cfrac {4}{1+{\cfrac {1^{2}}{3+{\cfrac {2^{2}}{5+{\cfrac {3^{2}}{7+{\cfrac {4^{2}}{9+\ddots }}}}}}}}}}=3+{\cfrac {1^{2}}{5+{\cfrac {4^{2}}{7+{\cfrac {3^{2}}{9+{\cfrac {6^{2}}{11+{\cfrac {5^{2}}{13+\ddots }}}}}}}}}}}

The remainder of the MadhavaLeibniz series can be expressed as generalized continued fraction as follows.

    π
    =
    4
    
      ∑
      
        n
        =
        1
      
      
        m
      
    
    
      
        
          (
          
          1
          
            )
            
              n
              
              1
            
          
        
        
          2
          n
          
          1
        
      
    
    +
    
      
        
          
            
          
          
            
              2
              (
              
              1
              
                )
                
                  m
                
              
            
          
        
        
          
            
          
          
            
              2
              m
              +
              
                
                  
                    
                      
                    
                    
                      
                        
                          1
                          
                            2
                          
                        
                      
                    
                  
                  
                    
                      
                    
                    
                      
                        2
                        m
                        +
                        
                          
                            
                              
                                
                              
                              
                                
                                  
                                    2
                                    
                                      2
                                    
                                  
                                
                              
                            
                            
                              
                                
                              
                              
                                
                                  2
                                  m
                                  +
                                  
                                    
                                      
                                        
                                          
                                        
                                        
                                          
                                            
                                              3
                                              
                                                2
                                              
                                            
                                          
                                        
                                      
                                      
                                        
                                          
                                        
                                        
                                          
                                            2
                                            m
                                            +
                                            ⋱
                                          
                                        
                                      
                                    
                                  
                                
                              
                            
                          
                        
                      
                    
                  
                
              
            
          
        
      
    
    
    (
    m
    =
    1
    ,
    2
    ,
    3
    ,
    …
    )
  

{\displaystyle \pi =4\sum _{n=1}^{m}{\frac {(-1)^{n-1}}{2n-1}}+{\cfrac {2(-1)^{m}}{2m+{\cfrac {1^{2}}{2m+{\cfrac {2^{2}}{2m+{\cfrac {3^{2}}{2m+\ddots }}}}}}}}\qquad (m=1,2,3,\ldots )}

Note that Madhava's correction term is

        2
        
          2
          m
          +
          
            
              
                1
                
                  2
                
              
              
                2
                m
                +
                
                  
                    
                      2
                      
                        2
                      
                    
                    
                      2
                      m
                    
                  
                
              
            
          
        
      
    
    =
    4
    
      
        
          
            m
            
              2
            
          
          +
          1
        
        
          4
          
            m
            
              3
            
          
          +
          5
          m
        
      
    
  

{\displaystyle {\frac {2}{2m+{\frac {1^{2}}{2m+{\frac {2^{2}}{2m}}}}}}=4{\frac {m^{2}+1}{4m^{3}+5m}}}

. The well-known values 22/7 and 355/113 are respectively the second and fourth continued fraction approximations to π.

=== Trigonometry ===

==== GregoryLeibniz series ==== The GregoryLeibniz series

    π
    =
    4
    
      ∑
      
        n
        =
        0
      
      
        ∞
      
    
    
      
        
          
            
          
          
            
              (
              
              1
              
                )
                
                  n
                
              
            
          
        
        
          
            
          
          
            
              2
              n
              +
              1
            
          
        
      
    
    =
    4
    
      (
      
        
          
            1
            1
          
        
        
        
          
            1
            3
          
        
        +
        
          
            1
            5
          
        
        
        
          
            1
            7
          
        
        +
        
        ⋯
      
      )
    
  

{\displaystyle \pi =4\sum _{n=0}^{\infty }{\cfrac {(-1)^{n}}{2n+1}}=4\left({\frac {1}{1}}-{\frac {1}{3}}+{\frac {1}{5}}-{\frac {1}{7}}+-\cdots \right)}

is the power series for arctan(x) specialized to x = 1. It converges too slowly to be of practical interest. However, the power series converges much faster for smaller values of

    x
  

{\displaystyle x}

, which leads to formulae where

    π
  

{\displaystyle \pi }

arises as the sum of small angles with rational tangents, known as Machin-like formulae.

==== Arctangent ====

Knowing that 4 arctan 1 = π, the formula can be simplified to get:

            π
          
          
            
            =
            2
            
              (
              
                1
                +
                
                  
                    
                      
                        
                      
                      
                        
                          1
                        
                      
                    
                    
                      
                        
                      
                      
                        
                          3
                        
                      
                    
                  
                
                +
                
                  
                    
                      
                        
                      
                      
                        
                          1
                          ⋅
                          2
                        
                      
                    
                    
                      
                        
                      
                      
                        
                          3
                          ⋅
                          5
                        
                      
                    
                  
                
                +
                
                  
                    
                      
                        
                      
                      
                        
                          1
                          ⋅
                          2
                          ⋅
                          3
                        
                      
                    
                    
                      
                        
                      
                      
                        
                          3
                          ⋅
                          5
                          ⋅
                          7
                        
                      
                    
                  
                
                +
                
                  
                    
                      
                        
                      
                      
                        
                          1
                          ⋅
                          2
                          ⋅
                          3
                          ⋅
                          4
                        
                      
                    
                    
                      
                        
                      
                      
                        
                          3
                          ⋅
                          5
                          ⋅
                          7
                          ⋅
                          9
                        
                      
                    
                  
                
                +
                
                  
                    
                      
                        
                      
                      
                        
                          1
                          ⋅
                          2
                          ⋅
                          3
                          ⋅
                          4
                          ⋅
                          5
                        
                      
                    
                    
                      
                        
                      
                      
                        
                          3
                          ⋅
                          5
                          ⋅
                          7
                          ⋅
                          9
                          ⋅
                          11
                        
                      
                    
                  
                
                +
                ⋯
              
              )
            
          
        
        
          
          
            
            =
            2
            
              ∑
              
                n
                =
                0
              
              
                ∞
              
            
            
              
                
                  
                    
                  
                  
                    
                      n
                      !
                    
                  
                
                
                  
                    
                  
                  
                    
                      (
                      2
                      n
                      +
                      1
                      )
                      !
                      !
                    
                  
                
              
            
            =
            
              ∑
              
                n
                =
                0
              
              
                ∞
              
            
            
              
                
                  
                    
                  
                  
                    
                      
                        2
                        
                          n
                          +
                          1
                        
                      
                      n
                      
                        !
                        
                          2
                        
                      
                    
                  
                
                
                  
                    
                  
                  
                    
                      (
                      2
                      n
                      +
                      1
                      )
                      !
                    
                  
                
              
            
            =
            
              ∑
              
                n
                =
                0
              
              
                ∞
              
            
            
              
                
                  
                    
                  
                  
                    
                      
                        2
                        
                          n
                          +
                          1
                        
                      
                    
                  
                
                
                  
                    
                  
                  
                    
                      
                        
                          
                            (
                          
                          
                            
                              2
                              n
                            
                            n
                          
                          
                            )
                          
                        
                      
                      (
                      2
                      n
                      +
                      1
                      )
                    
                  
                
              
            
          
        
        
          
          
            
            =
            2
            +
            
              
                2
                3
              
            
            +
            
              
                4
                15
              
            
            +
            
              
                4
                35
              
            
            +
            
              
                16
                315
              
            
            +
            
              
                16
                693
              
            
            +
            
              
                32
                3003
              
            
            +
            
              
                32
                6435
              
            
            +
            
              
                256
                109395
              
            
            +
            
              
                256
                230945
              
            
            +
            ⋯
          
        
      
    
  

{\displaystyle {\begin{aligned}\pi &=2\left(1+{\cfrac {1}{3}}+{\cfrac {1\cdot 2}{3\cdot 5}}+{\cfrac {1\cdot 2\cdot 3}{3\cdot 5\cdot 7}}+{\cfrac {1\cdot 2\cdot 3\cdot 4}{3\cdot 5\cdot 7\cdot 9}}+{\cfrac {1\cdot 2\cdot 3\cdot 4\cdot 5}{3\cdot 5\cdot 7\cdot 9\cdot 11}}+\cdots \right)\\&=2\sum _{n=0}^{\infty }{\cfrac {n!}{(2n+1)!!}}=\sum _{n=0}^{\infty }{\cfrac {2^{n+1}n!^{2}}{(2n+1)!}}=\sum _{n=0}^{\infty }{\cfrac {2^{n+1}}{{\binom {2n}{n}}(2n+1)}}\\&=2+{\frac {2}{3}}+{\frac {4}{15}}+{\frac {4}{35}}+{\frac {16}{315}}+{\frac {16}{693}}+{\frac {32}{3003}}+{\frac {32}{6435}}+{\frac {256}{109395}}+{\frac {256}{230945}}+\cdots \end{aligned}}}

with a convergence such that each additional 10 terms yields at least three more digits.

    π
    =
    2
    +
    
      
        1
        3
      
    
    
      (
      
        2
        +
        
          
            2
            5
          
        
        
          (
          
            2
            +
            
              
                3
                7
              
            
            
              (
              
                2
                +
                ⋯
              
              )
            
          
          )
        
      
      )
    
  

{\displaystyle \pi =2+{\frac {1}{3}}\left(2+{\frac {2}{5}}\left(2+{\frac {3}{7}}\left(2+\cdots \right)\right)\right)}

This series is the basis for a decimal spigot algorithm by Rabinowitz and Wagon.

Another formula for

    π
  

{\displaystyle \pi }

involving arctangent function is given by

        π
        
          2
          
            k
            +
            1
          
        
      
    
    =
    arctan
    
    
      
        
          2
          
          
            a
            
              k
              
              1
            
          
        
        
          a
          
            k
          
        
      
    
    ,
    
    
    k
    ≥
    2
    ,
  

{\displaystyle {\frac {\pi }{2^{k+1}}}=\arctan {\frac {\sqrt {2-a_{k-1}}}{a_{k}}},\qquad \qquad k\geq 2,}

where

      a
      
        k
      
    
    =
    
      
        2
        +
        
          a
          
            k
            
            1
          
        
      
    
  

{\displaystyle a_{k}={\sqrt {2+a_{k-1}}}}

such that

      a
      
        1
      
    
    =
    
      
        2
      
    
  

{\displaystyle a_{1}={\sqrt {2}}}

. Approximations can be made by using, for example, the rapidly convergent Euler formula

    arctan
    
    (
    x
    )
    =
    
      ∑
      
        n
        =
        0
      
      
        ∞
      
    
    
      
        
          
            2
            
              2
              n
            
          
          (
          n
          !
          
            )
            
              2
            
          
        
        
          (
          2
          n
          +
          1
          )
          !
        
      
    
    
    
      
        
          x
          
            2
            n
            +
            1
          
        
        
          (
          1
          +
          
            x
            
              2
            
          
          
            )
            
              n
              +
              1
            
          
        
      
    
    .
  

{\displaystyle \arctan(x)=\sum _{n=0}^{\infty }{\frac {2^{2n}(n!)^{2}}{(2n+1)!}}\;{\frac {x^{2n+1}}{(1+x^{2})^{n+1}}}.}

Alternatively, the following simple expansion series of the arctangent function can be used

    arctan
    
    (
    x
    )
    =
    2
    
      ∑
      
        n
        =
        1
      
      
        ∞
      
    
    
      
        
          1
          
            2
            n
            
            1
          
        
      
      
        
          
            
              
                
                  a
                
                
                  n
                
              
            
            
              (
              x
              )
            
          
          
            
              a
              
                n
              
              
                2
              
            
            
              (
              x
              )
            
            +
            
              b
              
                n
              
              
                2
              
            
            
              (
              x
              )
            
          
        
      
    
    ,
  

{\displaystyle \arctan(x)=2\sum _{n=1}^{\infty }{{\frac {1}{2n-1}}{\frac {{{a}_{n}}\left(x\right)}{a_{n}^{2}\left(x\right)+b_{n}^{2}\left(x\right)}}},}

where

              a
              
                1
              
            
            (
            x
            )
            =
            2
            
              /
            
            x
            ,
          
        
        
          
          
            
              b
              
                1
              
            
            (
            x
            )
            =
            1
            ,
          
        
        
          
          
            
              a
              
                n
              
            
            (
            x
            )
            =
            
              a
              
                n
                
                1
              
            
            (
            x
            )
            
            
              (
              
                1
                
                4
                
                  /
                
                
                  x
                  
                    2
                  
                
              
              )
            
            +
            4
            
              b
              
                n
                
                1
              
            
            (
            x
            )
            
              /
            
            x
            ,
          
        
        
          
          
            
              b
              
                n
              
            
            (
            x
            )
            =
            
              b
              
                n
                
                1
              
            
            (
            x
            )
            
            
              (
              
                1
                
                4
                
                  /
                
                
                  x
                  
                    2
                  
                
              
              )
            
            
            4
            
              a
              
                n
                
                1
              
            
            (
            x
            )
            
              /
            
            x
            ,
          
        
      
    
  

{\displaystyle {\begin{aligned}&a_{1}(x)=2/x,\\&b_{1}(x)=1,\\&a_{n}(x)=a_{n-1}(x)\,\left(1-4/x^{2}\right)+4b_{n-1}(x)/x,\\&b_{n}(x)=b_{n-1}(x)\,\left(1-4/x^{2}\right)-4a_{n-1}(x)/x,\end{aligned}}}

to approximate

    π
  

{\displaystyle \pi }

with even more rapid convergence. Convergence in this arctangent formula for

    π
  

{\displaystyle \pi }

improves as integer

    k
  

{\displaystyle k}

increases. The constant

    π
  

{\displaystyle \pi }

can also be expressed by infinite sum of arctangent functions as