993 lines
15 KiB
Markdown
993 lines
15 KiB
Markdown
---
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title: "Bra–ket notation"
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chunk: 7/8
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source: "https://en.wikipedia.org/wiki/Bra–ket_notation"
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category: "reference"
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tags: "science, encyclopedia"
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date_saved: "2026-05-05T14:40:03.882193+00:00"
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instance: "kb-cron"
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---
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ψ
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ϕ
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,
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⊗
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ϕ
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,
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ψ
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,
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ψ
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,
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ϕ
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.
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{\displaystyle |\psi \rangle |\phi \rangle \,,\quad |\psi \rangle \otimes |\phi \rangle \,,\quad |\psi \phi \rangle \,,\quad |\psi ,\phi \rangle \,.}
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See quantum entanglement and the EPR paradox for applications of this product.
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== The unit operator ==
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Consider a complete orthonormal system (basis),
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{
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∈
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N
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}
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,
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{\displaystyle \{e_{i}\ |\ i\in \mathbb {N} \}\,,}
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for a Hilbert space H, with respect to the norm from an inner product ⟨·,·⟩.
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From basic functional analysis, it is known that any ket
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ψ
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⟩
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{\displaystyle |\psi \rangle }
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can also be written as
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⟩
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,
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{\displaystyle |\psi \rangle =\sum _{i\in \mathbb {N} }\langle e_{i}|\psi \rangle |e_{i}\rangle ,}
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with ⟨·|·⟩ the inner product on the Hilbert space.
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From the commutativity of kets with (complex) scalars, it follows that
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∑
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=
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{\displaystyle \sum _{i\in \mathbb {N} }|e_{i}\rangle \langle e_{i}|=\mathbb {I} }
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must be the identity operator, which sends each vector to itself.
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This, then, can be inserted in any expression without affecting its value; for example
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{\displaystyle {\begin{aligned}\langle v|w\rangle &=\langle v|\left(\sum _{i\in \mathbb {N} }|e_{i}\rangle \langle e_{i}|\right)|w\rangle \\&=\langle v|\left(\sum _{i\in \mathbb {N} }|e_{i}\rangle \langle e_{i}|\right)\left(\sum _{j\in \mathbb {N} }|e_{j}\rangle \langle e_{j}|\right)|w\rangle \\&=\langle v|e_{i}\rangle \langle e_{i}|e_{j}\rangle \langle e_{j}|w\rangle \,,\end{aligned}}}
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where, in the last line, the Einstein summation convention has been used to avoid clutter.
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In quantum mechanics, it often occurs that little or no information about the inner product ⟨ψ|φ⟩ of two arbitrary (state) kets is present, while it is still possible to say something about the expansion coefficients ⟨ψ|ei⟩ = ⟨ei|ψ⟩* and ⟨ei|φ⟩ of those vectors with respect to a specific (orthonormalized) basis. In this case, it is particularly useful to insert the unit operator into the bracket one time or more.
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For more information, see Resolution of the identity,
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{\displaystyle {\mathbb {I} }=\int \!dx~|x\rangle \langle x|=\int \!dp~|p\rangle \langle p|,}
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where
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p
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ℏ
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{\displaystyle |p\rangle =\int dx{\frac {e^{ixp/\hbar }|x\rangle }{\sqrt {2\pi \hbar }}}.}
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Since ⟨x′|x⟩ = δ(x − x′), plane waves follow,
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{\displaystyle \langle x|p\rangle ={\frac {e^{ixp/\hbar }}{\sqrt {2\pi \hbar }}}.}
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In his book (1958), Ch. III.20, Dirac defines the standard ket which, up to a normalization, is the translationally invariant momentum eigenstate
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ϖ
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⟩
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lim
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→
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{\textstyle |\varpi \rangle =\lim _{p\to 0}|p\rangle }
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in the momentum representation, i.e.,
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p
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{\displaystyle {\hat {p}}|\varpi \rangle =0}
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. Consequently, the corresponding wavefunction is a constant,
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{\displaystyle \langle x|\varpi \rangle {\sqrt {2\pi \hbar }}=1}
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, and
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−
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,
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{\displaystyle |x\rangle =\delta ({\hat {x}}-x)|\varpi \rangle {\sqrt {2\pi \hbar }},}
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as well as
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p
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exp
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p
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/
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ℏ
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)
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ϖ
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{\displaystyle |p\rangle =\exp(ip{\hat {x}}/\hbar )|\varpi \rangle .}
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Typically, when all matrix elements of an operator such as
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{\displaystyle \langle x|A|y\rangle }
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are available, this resolution serves to reconstitute the full operator,
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∫
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A
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y
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=
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A
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{\displaystyle \int dx\,dy\,|x\rangle \langle x|A|y\rangle \langle y|=A\,.}
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== Notation used by mathematicians ==
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The object physicists are considering when using bra–ket notation is a Hilbert space (a complete inner product space).
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Let
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(
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H
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,
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⟨
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⋅
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,
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⋅
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⟩
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)
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{\displaystyle ({\mathcal {H}},\langle \cdot ,\cdot \rangle )}
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be a Hilbert space and h ∈ H a vector in H. What physicists would denote by |h⟩ is the vector itself. That is,
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h
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H
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{\displaystyle |h\rangle \in {\mathcal {H}}.}
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Let H* be the dual space of H. This is the space of linear functionals on H. The embedding
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Φ
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:
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H
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↪
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∗
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{\displaystyle \Phi :{\mathcal {H}}\hookrightarrow {\mathcal {H}}^{*}}
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is defined by
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Φ
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h
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=
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φ
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h
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{\displaystyle \Phi (h)=\varphi _{h}}
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, where for every h ∈ H the linear functional
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φ
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h
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:
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H
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→
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C
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{\displaystyle \varphi _{h}:{\mathcal {H}}\to \mathbb {C} }
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satisfies for every g ∈ H the functional equation
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φ
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h
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(
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g
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)
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=
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⟨
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h
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,
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g
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⟩
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=
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⟨
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h
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∣
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g
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{\displaystyle \varphi _{h}(g)=\langle h,g\rangle =\langle h\mid g\rangle }
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.
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Notational confusion arises when identifying φh and g with ⟨h| and |g⟩ respectively. This is because of literal symbolic substitutions. Let
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φ
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h
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=
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H
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=
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⟨
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||
h
|
||
∣
|
||
|
||
|
||
{\displaystyle \varphi _{h}=H=\langle h\mid }
|
||
|
||
and let g = G = |g⟩. This gives
|
||
|
||
|
||
|
||
|
||
|
||
φ
|
||
|
||
h
|
||
|
||
|
||
(
|
||
g
|
||
)
|
||
=
|
||
H
|
||
(
|
||
g
|
||
)
|
||
=
|
||
H
|
||
(
|
||
G
|
||
)
|
||
=
|
||
⟨
|
||
h
|
||
|
||
|
|
||
|
||
(
|
||
G
|
||
)
|
||
=
|
||
⟨
|
||
h
|
||
|
||
|
|
||
|
||
|
||
|
||
(
|
||
|
||
|
||
|
||
|
|
||
|
||
g
|
||
⟩
|
||
|
||
|
||
)
|
||
|
||
|
||
|
||
.
|
||
|
||
|
||
{\displaystyle \varphi _{h}(g)=H(g)=H(G)=\langle h|(G)=\langle h|{\bigl (}|g\rangle {\bigr )}\,.}
|
||
|