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Bar product 1/1 https://en.wikipedia.org/wiki/Bar_product reference science, encyclopedia 2026-05-05T14:39:58.994259+00:00 kb-cron

In information theory, the bar product of two linear codes C2 ⊆ C1 is defined as

      C
      
        1
      
    
    
    
      C
      
        2
      
    
    =
    {
    (
    
      c
      
        1
      
    
    
    
      c
      
        1
      
    
    +
    
      c
      
        2
      
    
    )
    :
    
      c
      
        1
      
    
    ∈
    
      C
      
        1
      
    
    ,
    
      c
      
        2
      
    
    ∈
    
      C
      
        2
      
    
    }
    ,
  

{\displaystyle C_{1}\mid C_{2}=\{(c_{1}\mid c_{1}+c_{2}):c_{1}\in C_{1},c_{2}\in C_{2}\},}

where (a | b) denotes the concatenation of a and b. If the code words in C1 are of length n, then the code words in C1 | C2 are of length 2n. The bar product is an especially convenient way of expressing the ReedMuller RM(d, r) code in terms of the ReedMuller codes RM(d 1, r) and RM(d 1, r 1). The bar product is also referred to as the | u | u + v | construction or (u | u + v) construction.

== Properties ==

=== Rank === The rank of the bar product is the sum of the two ranks:

    rank
    
    (
    
      C
      
        1
      
    
    
    
      C
      
        2
      
    
    )
    =
    rank
    
    (
    
      C
      
        1
      
    
    )
    +
    rank
    
    (
    
      C
      
        2
      
    
    )
    
  

{\displaystyle \operatorname {rank} (C_{1}\mid C_{2})=\operatorname {rank} (C_{1})+\operatorname {rank} (C_{2})\,}

==== Proof ==== Let

    {
    
      x
      
        1
      
    
    ,
    …
    ,
    
      x
      
        k
      
    
    }
  

{\displaystyle \{x_{1},\ldots ,x_{k}\}}

be a basis for

      C
      
        1
      
    
  

{\displaystyle C_{1}}

and let

    {
    
      y
      
        1
      
    
    ,
    …
    ,
    
      y
      
        l
      
    
    }
  

{\displaystyle \{y_{1},\ldots ,y_{l}\}}

be a basis for

      C
      
        2
      
    
  

{\displaystyle C_{2}}

. Then the set

    {
    (
    
      x
      
        i
      
    
    
    
      x
      
        i
      
    
    )
    
    1
    ≤
    i
    ≤
    k
    }
    
    {
    (
    0
    
    
      y
      
        j
      
    
    )
    
    1
    ≤
    j
    ≤
    l
    }
  

{\displaystyle \{(x_{i}\mid x_{i})\mid 1\leq i\leq k\}\cup \{(0\mid y_{j})\mid 1\leq j\leq l\}}

is a basis for the bar product

      C
      
        1
      
    
    
    
      C
      
        2
      
    
  

{\displaystyle C_{1}\mid C_{2}}

.

=== Hamming weight === The Hamming weight w of the bar product is the lesser of (a) twice the weight of C1, and (b) the weight of C2:

    w
    (
    
      C
      
        1
      
    
    
    
      C
      
        2
      
    
    )
    =
    min
    {
    2
    w
    (
    
      C
      
        1
      
    
    )
    ,
    w
    (
    
      C
      
        2
      
    
    )
    }
    .
    
  

{\displaystyle w(C_{1}\mid C_{2})=\min\{2w(C_{1}),w(C_{2})\}.\,}

==== Proof ==== For all

      c
      
        1
      
    
    ∈
    
      C
      
        1
      
    
  

{\displaystyle c_{1}\in C_{1}}

,

    (
    
      c
      
        1
      
    
    
    
      c
      
        1
      
    
    +
    0
    )
    ∈
    
      C
      
        1
      
    
    
    
      C
      
        2
      
    
  

{\displaystyle (c_{1}\mid c_{1}+0)\in C_{1}\mid C_{2}}

which has weight

    2
    w
    (
    
      c
      
        1
      
    
    )
  

{\displaystyle 2w(c_{1})}

. Equally

    (
    0
    
    
      c
      
        2
      
    
    )
    ∈
    
      C
      
        1
      
    
    
    
      C
      
        2
      
    
  

{\displaystyle (0\mid c_{2})\in C_{1}\mid C_{2}}

for all

      c
      
        2
      
    
    ∈
    
      C
      
        2
      
    
  

{\displaystyle c_{2}\in C_{2}}

and has weight

    w
    (
    
      c
      
        2
      
    
    )
  

{\displaystyle w(c_{2})}

. So minimising over

      c
      
        1
      
    
    ∈
    
      C
      
        1
      
    
    ,
    
      c
      
        2
      
    
    ∈
    
      C
      
        2
      
    
  

{\displaystyle c_{1}\in C_{1},c_{2}\in C_{2}}

we have

    w
    (
    
      C
      
        1
      
    
    
    
      C
      
        2
      
    
    )
    ≤
    min
    {
    2
    w
    (
    
      C
      
        1
      
    
    )
    ,
    w
    (
    
      C
      
        2
      
    
    )
    }
  

{\displaystyle w(C_{1}\mid C_{2})\leq \min\{2w(C_{1}),w(C_{2})\}}

Now let

      c
      
        1
      
    
    ∈
    
      C
      
        1
      
    
  

{\displaystyle c_{1}\in C_{1}}

and

      c
      
        2
      
    
    ∈
    
      C
      
        2
      
    
  

{\displaystyle c_{2}\in C_{2}}

, not both zero. If

      c
      
        2
      
    
    ≠
    0
  

{\displaystyle c_{2}\not =0}

then:

            w
            (
            
              c
              
                1
              
            
            
            
              c
              
                1
              
            
            +
            
              c
              
                2
              
            
            )
          
          
            
            =
            w
            (
            
              c
              
                1
              
            
            )
            +
            w
            (
            
              c
              
                1
              
            
            +
            
              c
              
                2
              
            
            )
          
        
        
          
          
            
            ≥
            w
            (
            
              c
              
                1
              
            
            +
            
              c
              
                1
              
            
            +
            
              c
              
                2
              
            
            )
          
        
        
          
          
            
            =
            w
            (
            
              c
              
                2
              
            
            )
          
        
        
          
          
            
            ≥
            w
            (
            
              C
              
                2
              
            
            )
          
        
      
    
  

{\displaystyle {\begin{aligned}w(c_{1}\mid c_{1}+c_{2})&=w(c_{1})+w(c_{1}+c_{2})\\&\geq w(c_{1}+c_{1}+c_{2})\\&=w(c_{2})\\&\geq w(C_{2})\end{aligned}}}

If

      c
      
        2
      
    
    =
    0
  

{\displaystyle c_{2}=0}

then

            w
            (
            
              c
              
                1
              
            
            
            
              c
              
                1
              
            
            +
            
              c
              
                2
              
            
            )
          
          
            
            =
            2
            w
            (
            
              c
              
                1
              
            
            )
          
        
        
          
          
            
            ≥
            2
            w
            (
            
              C
              
                1
              
            
            )
          
        
      
    
  

{\displaystyle {\begin{aligned}w(c_{1}\mid c_{1}+c_{2})&=2w(c_{1})\\&\geq 2w(C_{1})\end{aligned}}}

so

    w
    (
    
      C
      
        1
      
    
    
    
      C
      
        2
      
    
    )
    ≥
    min
    {
    2
    w
    (
    
      C
      
        1
      
    
    )
    ,
    w
    (
    
      C
      
        2
      
    
    )
    }
  

{\displaystyle w(C_{1}\mid C_{2})\geq \min\{2w(C_{1}),w(C_{2})\}}

== See also == ReedMuller code

== References ==