241 lines
3.3 KiB
Markdown
241 lines
3.3 KiB
Markdown
---
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title: "Astronomia nova"
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chunk: 8/11
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source: "https://en.wikipedia.org/wiki/Astronomia_nova"
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category: "reference"
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tags: "science, encyclopedia"
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date_saved: "2026-05-05T16:09:34.057453+00:00"
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instance: "kb-cron"
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---
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In the diagram above,
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A
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{\textstyle A}
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is the sun and
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B
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{\textstyle B}
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is the center of the circle;
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G
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{\textstyle G}
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is aphelion and
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D
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{\textstyle D}
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is the planet. The area of the sector
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G
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A
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D
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{\textstyle GAD}
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is the area swept by the line drawn from the planet to the sun. From the area law, this is proportional to the time that the planet has traversed the segment
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G
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D
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{\textstyle GD}
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in its orbit, and therefore also the mean anomaly. Thus the area
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G
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A
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D
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{\textstyle GAD}
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gives the mean anomaly. The eccentric anomaly is defined by the angle
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∠
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G
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B
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D
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{\textstyle \angle GBD}
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. Since the angle of a sector, centered on a circle, is always proportional to its area, we can also express this by the area
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G
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B
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D
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{\textstyle GBD}
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. The relation between these two areas gives the relation between the mean anomaly (and therefore time) and eccentric anomaly.
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From the diagram, it is clear that the mean anomaly is simply the eccentric anomaly plus the area of the triangle
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D
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A
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B
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{\textstyle DAB}
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. The base of this triangle
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A
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B
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¯
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{\textstyle {\overline {AB}}}
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is the eccentricity of the circle, and the height of the triangle is proportional to sine of the eccentric anomaly. This is the Kepler equation. If we write
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M
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{\textstyle M}
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for the mean anomaly,
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E
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{\textstyle E}
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for the eccentric anomaly, and
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e
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{\textstyle e}
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for the eccentricity, then this can be written as:
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M
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=
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E
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+
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e
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sin
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(
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E
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)
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{\displaystyle M=E+e\sin(E)}
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Kepler further shows that the true anomaly is given by the eccentric anomaly plus the angle
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∠
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D
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B
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A
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{\textstyle \angle DBA}
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. Kepler refers to the angle
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∠
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D
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B
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A
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{\textstyle \angle DBA}
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as the optical equation. For low eccentricities, this angle is approximately twice the area of the triangle
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D
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B
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A
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{\textstyle DBA}
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. If we write the true anomaly as
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ϑ
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{\textstyle \vartheta }
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, this gives the formula:
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ϑ
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≈
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E
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+
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2
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e
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sin
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(
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E
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)
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{\displaystyle \vartheta \approx E+2e\sin(E)}
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